(8y^8/2x^4)^-3

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Solution for (8y^8/2x^4)^-3 equation: 


D( x )

x^4*((8*y^8)/2) = 0

x^4*((8*y^8)/2) = 0

x^4*((8*y^8)/2) = 0

4*x^4*y^8 = 0 // : 4*y^8

x^4 = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^4*((8*y^8)/2))^-3 = 0

1/64*x^-12*y^-24 = 0 // : 1/64*y^-24

x^-12 = 0

x naleu017Cy do O

x belongs to the empty set

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